27 February 2019
- Last edited 27 February 2019
Another way is:
Say the beam has 11 nodes (1-11), thus 10 elements (n_el). Here nodes go from one end (node 1) to the other end of the beam (node nr. 11).
For every node one will have a force vs time table (see here for details on tables: https://www.ozeninc.com/apdl-arrays-tables-quickreference/), and an associated force, F command.
Say the first node starts with a force that starts immediately and is then zero, now say at the middle (node nr 6) the force has a value of whatever that you have (just say 100N) and is on at time equal to LengthBeam/2/vspeed., and is zero elsewhere (that is for other time except of t=(Lengthbeam/2)/(speed)).
So the force is on (has a value) in the force time table when t_n= ((n-1)*L/n_el)/speed, where t_n is the active time for node n, and n_el are number of elements.
Thus for a beam 1 m long and a force travelling at a speed of 1m/s, then at the middle (node nr. 6) t_6 = 0.5 s, using the above.
For 1/5 of the beam distance (node nr. 3) t_3 = 0.2 s, using the above, and so on.