Non-Linear Axisymmetric Analysis

  • 21 Views
  • Last Post 09 April 2020
  • Topic Is Solved
AkashVyas posted this 08 April 2020

Hello Everyone, I'm currently working on a non-Linear problem of the sliding seal, I already have a solved solid model of this but I'm trying to reduce the computation time, as it is an axisymmetric model.

solid model

I have given input displacement of 3.8mm as shown in this image input

as this solid model was successful and the reaction force at the seal where displacement is applied, is shown in the image,output force 

and I have also tried this problem axisymmetric model, with the same input and my reaction force value is 

so my question is why the forces in the solid and axisymmetric model are almost the same.

Order By: Standard | Newest | Votes
peteroznewman posted this 08 April 2020

It would be good if you used Excel and put the displacement and force for the solid model in columns A and B and the displacement and force for the axisymmetric model in columns C and D because you have 5 time steps in one and 1 time step in the other so it is hard to compare using the images you provided but would be easy if you overlaid the two curves on the same scale.

If you have the same physics and the same inputs, I would expect to get the same outputs from an axisymmetric model and a 3D model. Maybe I don't understand your question.

AkashVyas posted this 09 April 2020

I got you point but then why the reaction forces for 1/4 model is less then complete solid model.

peteroznewman posted this 09 April 2020

The reaction force of a 1/4 solid model should be 1/4 of the reaction force for a complete solid model if you are applying the same displacement.

Close