20 February 2018
- Last edited 20 February 2018
I copy/paste the paragraph from my first reply.
A Static Structural model will calculate the stress in the sandstone and the bolt for a specific load. The result is the maximum stress in each part. You need to compare the maximum stress with the strength of the material. If the stress < strength, then no failure or damage is predicted to occur in a physical test. If the stress > strength, then failure or damage is predicted to occur in a physical test, but you won't see that in the simulation, that happens only when you compare with the strength.
A Static Structural model is useful to predict the load when failure would occur in a physical sample, but the simulation won't show the failure. Results from the model will only provide stress values. Those values are compared with the value for strength and will be evidence that failure would or would not occur in a physical test.
Your model has some severe problems. If you hide the bolt and resin, you will see that the cube has a standing piece the size of the bolt. You need to subtract the bolt from the cube to fix this. Your mesh is far too coarse. You need several elements through the steel bar, and the resin. You have only a single element. These changes will stop the weird appearance of the top of the bar in the deformation plot.
One way to reduce the size of the model is to open DesignModeler, and add two planes of Symmetry. Then you will have only 1/4 of the volume to mesh. Another way to reduce the size of the model is to cut away more sandstone and make it smaller, same with the bolt. I have meshed this model and biased elements close to the region of interest, which is where the bolt emerges from the top of the cube. I have however, kept the number of nodes + elements below the Student license limit of 32K. Since this is a 1/4 model, only 1/4 of the force is applied to the top of the bolt. Since I was cutting down the size of the sandstone cube, I converted the side force into a pressure by dividing by the area. Since there are two symmetry planes, the bottom support can be z=0 displacement instead of a Fixed support. This has the benefit of allowing the side pressure to compress the cube uniformly.